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The quadratic x^2 + (a^2 - 5a + b + 4) x + b = 0 has roots -5 and 1.  Find the number of possible integer values of a.

 Jun 21, 2020
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(X+5)(x-1)= x^2+(a^2-5a+b+4)x + b       So b= -5      You can take it from here! cheeky

 Jun 21, 2020

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