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Find the non-zero value of $a$ such that the quadratic equation $ax^2+8x+4=6x-40$ has only one solution.

 Aug 26, 2023

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For a quadratic equation ax2+bx+c=0 to have only one solution, its discriminant b2−4ac must be equal to 0. In this case, we have b2−4ac=(8)2−4(a)(4)=0, so 64−16a=0 and a=4​.

 Aug 26, 2023
 #1
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Best Answer

For a quadratic equation ax2+bx+c=0 to have only one solution, its discriminant b2−4ac must be equal to 0. In this case, we have b2−4ac=(8)2−4(a)(4)=0, so 64−16a=0 and a=4​.

Guest Aug 26, 2023

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