For a quadratic equation ax2+bx+c=0 to have only one solution, its discriminant b2−4ac must be equal to 0. In this case, we have b2−4ac=(8)2−4(a)(4)=0, so 64−16a=0 and a=4.
For a quadratic equation ax2+bx+c=0 to have only one solution, its discriminant b2−4ac must be equal to 0. In this case, we have b2−4ac=(8)2−4(a)(4)=0, so 64−16a=0 and a=4.
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