The quadratic ax^2 + bx + c can be expressed in the form (x - 4)^2 + 8. When the quadratic is expressed in the form 3ax^2 + 3bx + 3c, what is n(x - h)^2 + k, what is h?
(x - 4)^2 + 8 =
x^2 -8x + 16 + 8
x^2 - 8x + 24 = ax^2 + bx + c
3ax^2 + 3bx + 3c =
3 ( ax^2 + bx + c) =
3 ( x^2 - 8x + 24 ) =
3 [ (x - 4)^2 + 8 ] =
3 (x -4)^2 + 24
h does not change......it still = 4
