The 'x' value of the vertex of the graph of this bowl shaped parabola will be given by - b / 2a where b = 9 a = -2
use this value of 'x' in the equation to find the 'y' coordinate of the vertex.....
Find the vertex of the graph of the equation y = -2x^2 + 9x - 18.
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\( y = -2x^2 + 9x - 18\\ y'=-4x+9=0\\ \color{blue}x_P= \frac{9}{4}\)
\( y = -2x^2 + 9x - 18\\ y=-2\cdot (2.25)^2 + 9\cdot 2.25) - 18\\ y=-10.125+20.25-18\\ \color{blue}y_P=-7.875\)
\(P_{vertex}(2.25,-7.875)\)
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