If we express 3x^2 - 6x - 2 + 12x - 7 in the form a(x - h)^2 + k, then what is a + h + k?
+179 Combine like terms to get..
\(3x^2+6x-9\)
Then isolate the $x^2$ and $x$ terms and we get \(3(x^2+2x) - 9\).
Then complete the square inside the parentheses to get \(3(x^2+2x+1) - 9 - 1 \cdot 3\) .
Then factor the parentheses and simplify to get \(3(x+1)^2 - 12\).
You should be able to finish from here.
