+0

0
185
1

The quadratic function f(x) satisfies f(1) = 2, f(2) = -7, f(4) = 13.  Find f(5).

Jul 10, 2020

#1
+8352
+1

Let f(x) = ax2 + bx + c.

$$\begin{cases}a + b + c = 2\\4a + 2b + c = -7\\16a + 4b + c = 13\end{cases}$$

Solving by matrix method(or whatever method you like):

$$\begin{bmatrix}a\\b\\c\end{bmatrix} = \begin{bmatrix}1&1&1\\4&2&1\\16&4&1\end{bmatrix}^{-1}\cdot \begin{bmatrix}2\\-7\\13\end{bmatrix} = \begin{bmatrix}\dfrac{19}3\\-28\\\dfrac{71}3\end{bmatrix}$$

Therefore $$f(x) = ax^2 + bx + c = \dfrac{19}3 x^2 - 28x + \dfrac{71}3$$

Substituting x = 5 gives the answer. I believe you can do it from here.

Jul 11, 2020