The quadratic ax^2 + bx + c can be expressed in the form 2(x - 8)^2 + 4. When the quadratic 3ax^2 + 3bx + 3c is expressed in the form n(x - h)^2 + k, what is h?
+128473 2(x - 8)^2 + 4 (expand)
2 (x^2 - 16x + 64) + 4 =
2x^2 - 32x + 128 + 4 =
2x^2 - 32x + 132 a = 2 b = -32 c = 132
So
3(2)x^2 + 3(-32)x + 3 (132) =
3 ( 4x^2 - 32x + 132) = (factor out 4)
3 * 4 ( x^2 - 8x + 33) =
12 [ x^2 - 8x + 16 + 17 ] = (factor x^2 - 8x + 16)
12 [ ( x - 4)^2 + 17 ] = (distribute the 12 across the terms in the brackets )
12 (x - 4)^2 + 204
h = 4
