quadratic

Here is one way to find the quadratic

$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$   =  (7+- sqrt23i)/2        so  a  =1   and b = -7

x^2 -7x + c              to find c      sqrt(  -7^2-4(1)(c))  = sqrt 23i        

                                  solving for c = 18

x^2-7x+18 =0