Find the quadratic with integer coefficients whose roots are \(\dfrac{-7 \pm \sqrt{23} i}{2}\)
+37146 Here is one way to find the quadratic
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) = (7+- sqrt23i)/2 so a =1 and b = -7
x^2 -7x + c to find c sqrt( -7^2-4(1)(c)) = sqrt 23i
solving for c = 18
x^2-7x+18 =0
