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x^2 + px + q = 0 has one negative solution and one positive solution.  If p = 3, then what are all the possible values of q?

 May 1, 2021
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q   must  be   negative  ( if it  were positive, we  would  have factors of ( x + m) ( x + n)  =  0, and the roots  m, n  would both be negative)

 

So......any  negative for q  would  work  because  the discriminant

 

3^2  - 4(q)(1)    will  be  positive

 

So

 

q  <  0

 

cool cool cool

 May 1, 2021

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