In an equation of the form with k = ax^2 + bx + c, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x - 12)(x - 8) , what is the least possible value for k?
(6x -12) ( x - 8) =
6x^2 -12x - 48x + 96 =
6x^2 - 60x + 96
The x coordinate ofthe vertex is -(-60) / (2 * 6) = 5
The minimum value for k is
(6 * 5 - 12) ( 5 - 8) =
(18) (-3) = - 54
