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In an equation of the form with k = ax^2 + bx + c, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x - 12)(x - 8) , what is the least possible value for k?

 Jun 26, 2022
 #1
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(6x  -12) ( x - 8)   =

 

6x^2 -12x - 48x + 96  =

 

6x^2 - 60x + 96

 

The x coordinate ofthe vertex is   -(-60) / (2 * 6)   =  5

 

The minimum value for  k  is

 

(6 * 5 - 12) ( 5 - 8)  =

 

(18) (-3)  =   - 54

 

 

cool cool cool

 Jun 26, 2022

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