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If $t$ is a real number, what is the maximum possible value of the expression $-t^2 + 8t -4$?

 Oct 19, 2021
 #1
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You get the minimum at t = -8, which gives you a minimum value of -4.

 Oct 19, 2021
 #2
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MAX   occurs at   t = - b/2a = - 8 /(2*-1) = 4 

    sub in t = 4 to find the max value is   12

 

(there is no minimum value....   - infinity)

 Oct 19, 2021
 #3
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ohh thank you for your help! i knew t = 0 but kept calculating as -4 for some reason. thanks (i cant give you plus 1 for some reason)

Guest Oct 19, 2021

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