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In an equation of the form with k = ax^2 + bx + c, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x + 12)(x - 18) , what is the least possible value for k?

 Apr 24, 2022

Best Answer 

 #2
avatar+122388 
-1

(6x + 12) (x  -18)  =   

 

6x^2 - 96x -  216

 

The  x coordinate of the  vertex =  (96) /(2 * 6)  =  96 /12  = 8

 

k is the  y coordinate of the  vertex and   =     (6 (8) + 12) (8  -18)  = 60 (-10)  =   -600

 

 

cool cool cool

 Apr 24, 2022
 #1
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0

The least possible value of k is -34.

 Apr 24, 2022
 #2
avatar+122388 
-1
Best Answer

(6x + 12) (x  -18)  =   

 

6x^2 - 96x -  216

 

The  x coordinate of the  vertex =  (96) /(2 * 6)  =  96 /12  = 8

 

k is the  y coordinate of the  vertex and   =     (6 (8) + 12) (8  -18)  = 60 (-10)  =   -600

 

 

cool cool cool

CPhill Apr 24, 2022

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