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Let r and s be the roots of 3x^2+4x-12=2x^2-6x+8. Find r^2 + s^2

 Nov 22, 2022
 #1
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Combine like terms: x^2 + 10x - 20

Manipulate: r^2 + s^2 = (r + s)^2 - 2rs

Vietas formula: r + s = -10, rs = -20

Substitution: (-10)^2 - 2(-20) = 100 + 40 = 140

 Nov 23, 2022

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