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avatar+1725 

Let a and b be the roots of the quadratic 2x^2 - 8x + 7 = x^2 - 14x + 2. Compute a^3/b^3 + b^3/a^3.

 Mar 19, 2024
 #1
avatar+129771 
+1

Simplify as

x^2 + 6x + 5  = 0 

(x + 5) ( x + 1)  = 0

x = -5    x  = -1

Let a  = -5   b = -1

 

a^3/b^3  + b^3 / a^3  =

 

(-5)^3 / ( -1)^3   + (-1)^3 / (-5)^3  =

 

125/1 + 1/125  =

 

125.008

 

cool cool cool

 Mar 19, 2024

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