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There exist constants a, h and k such that
x^2 + 12x + 4 = a(x - h)^2 + k
for all real numbers x. Enter the ordered triple (a,h,k).

 Feb 14, 2022
 #1
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Quadratics aren't exactly my strong spot... but I would play around with the equation a bit. Factor the left side?

In x^2 + 12x + 4, what two numbers multiply to 4 and add up to 12?

 Feb 14, 2022

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