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If the roots of the quadratic equation x^2/2 + 99x + c = 0  are \(x = -99 + \sqrt{9599}\) and \(x = -99 - \sqrt{9599}\), then what is the value of c?

 Jun 7, 2022
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By the quadratic formula, the roots are: \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\).

 

Substituting what we know, we have: \(x = {-99 \pm \sqrt{99^2-2c}}\)

 

Now, we have the equation: \(99^2 - 2c = 9959\)

 

Can you take it from here?

 Jun 7, 2022

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