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If the roots of the quadratic equation x^2/2 + 99x + c = 0  are $$x = -99 + \sqrt{9599}$$ and $$x = -99 - \sqrt{9599}$$, then what is the value of c?

Jun 7, 2022

#1
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By the quadratic formula, the roots are: $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$.

Substituting what we know, we have: $$x = {-99 \pm \sqrt{99^2-2c}}$$

Now, we have the equation: $$99^2 - 2c = 9959$$

Can you take it from here?

Jun 7, 2022