Determine the quadratic function f whose graph has the following, The vertex is (2,−1) and the other given point is (3,1) in form f(x) = ax^2+bx+c,
+2666 To solve this problem, use vertex form: \(y = a(x-h)^2 +k\), where the vertex occurs at \((h,k)\)
Substituting the vertex, we have: \(y = a(x-2)^2 - 1\).
Now, plugging in the point \((3,1)\) and solving for a tells us that \(a = 2\).
This means that the quadratic in vertex form is \(2(x-2)^2 - 1 = \color{brown}\boxed{2x^2 - 8x + 7}\)
