The equation y = -16t^2 + 28t + 180 describes the height (in feet) of a ball tossed up in the air at 28 feet per second from a height of 180 feet from the ground. In how many seconds will the ball hit the ground?

In how many seconds will the ball hit the ground?

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\(y = -16t^2 + 28t + 180\)

\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\\ t = {-28 \pm \sqrt{28^2-4\cdot (-16)\cdot 180} \over 2\cdot (-16)}\\ \color{blue}t=4.341 \)

In 4.341 seconds will the ball hit the ground.

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