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If f(0)=0,f(1)=2,f(2)=-5 and f(x)=ax^2+bx+c, what is the value of f(3)?

 Feb 7, 2022
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If f(0)=0 then 0=a(0)^2+b(0)+c, which means that c=0
If f(1)=2 then 2=a(1)^2+b(1), which means that a+b=2

If f(2)=-5 then -5=a(-5)^2+b(-5), which means that 25a-5b=-5, which means that b+5a=1

 

Solve the system of equations.

b+5a=1

b+a=2

4a=-1

a=-1/4

 

Solve for b and then plug in 3 for x. You should get your answer. Let me know if I did anything wrong!

 Feb 7, 2022
edited by InhumanCalculator  Feb 7, 2022

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