The quadratic x^2 - 6x + 60 can be written in the form (x + b)^2 + c, where b and c are constants. What is b + c?
The quadratic x^2 - 6x + 60 can be written in the form (x + b)^2 + c, where b and c are constants. What is b + c?
In the instance of x2 – 6x you need (6 / 2)2 to complete the square. So you have x2 – 6x + 9
(x – 3)2
To take that "9" on up to 60, simply add 51. The resulting equation becomes (x – 3)2 + 51
Per the terms of the problem, add b + c, that is, add 3 + 51, and the final answer is 54.
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