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Let r and s be the roots of 3x^2+4x-12=2x^2-6x+8. Find r^2 + s^2

 Nov 19, 2022
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r^2 + s^2 = (r + s)^2 - 2rs

 

 

3x^2 + 4x - 12 = 2x^2 - 6x + 8

Move all the terms to onside side

 

x^2 + 10x - 20 = 0 

 

Sum = - 10.

Product = - 20.

 

100 + 40 = 140. 

 Nov 19, 2022

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