Let r and s be the roots of 3x^2+4x-12=2x^2-6x+8. Find r^2 + s^2
r^2 + s^2 = (r + s)^2 - 2rs
3x^2 + 4x - 12 = 2x^2 - 6x + 8
Move all the terms to onside side
x^2 + 10x - 20 = 0
Sum = - 10.
Product = - 20.
100 + 40 = 140.
