Find constants a, h, k such that 3x^2 + 4x + 1 = a(x - h)^2 + k.
3x^2 + 4x + 1 = a( x + h)^2 + k
3x^2 + 4x + 1 = a (x^2 + 2xh + h^2) + k
3x^2 + 4x + 1 = ax^2 + 2ahx + ah^2 + k
a = 3
4 = 2ah
4 = 2(3)h
4 = 6h
h = 4/6 = 2/3
ah^2 + k = 1
3(2/3)^2 + k = 1
(4/3) + k = 1
k = 1 - 4/3
k = -1/3
