The equation y = -4.9t^2 - 3.5t + 12.4 relates the height y (in meters) to the elapsed time t (in seconds) for a ball thrown downward at 3.5 meters per second from a height of 12.4 meters from the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest hundredth.

Guest Feb 3, 2022

#1**+1 **

When the ball hits the ground, y=0

0 = -4.9 t^2-3.5t+12.4 Use Quadratic formula to solve for 't' Throw out the negative value

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ElectricPavlov Feb 3, 2022