+537 The graph of the equation \(y=ax^2+bx+c\), where a, b, and c are constants, is a parabola with an axis of symmetry as \(x=-3\). Find \(\frac{b}{a}\) .
+6251 \(\text{axis of symmetry at }x=-3 \Rightarrow\\ a(x+3)^2 + c = ax^2 + 6ax+ (9+c)\\ \dfrac{b}{a} = \dfrac{6a}{a} = 6\)
The cheater way to do it is to remember that the axis of symmetry is at
\(x = -\dfrac{b}{2a} \\ \text{so here}\\ -3 = -\dfrac{b}{2a} \\ \dfrac{b}{a} = (-3)(-2) = 6\)
