The difference of the roots of the quadratic equation $x^2 + bx + c = 0$ is $|b - 2c|$. If $c \neq 0$, then find $c$ in terms of $b$.
TYSM!
The difference of the roots = sqrt ( b^2 - 4ac) = sqrt ( b^2 - 4c)
And l b - 2c l can be written as sqrt [ (b - 2c)^2 ]
This implies that
b^2 - 4c = ( b - 2c)^2
b^2 - 4c = b^2 - 4bc + 4c^2
-4c = -4bc + 4c^2
c = bc - c^2
c^2 + c = bc
c + 1 = b
c = b - 1
