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The graph of the equation y=ax^2+bx-6 is completely below the x axis. If , a^2=49 what is the largest possible integral value of b?

Guest Jun 19, 2018
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This describes an upside down parabola (opens downward...looks like a dome)

so    a^2 = 49   means  a = -7

 

so you have   -7x^2+bx-6 =0        Using quadratic formula

 

\(0> {-b \pm \sqrt{b^2-4(7)(-6)} \over -14}\)   yields   b <12.96   and b  > -12.96  

                                                        so b<12.96 is the greatest value

ElectricPavlov  Jun 20, 2018

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