Find all real numbers $z$ for which the equation $(z-5)x^2-zx+5=0$ only has one real solution. If you find more than one, then list the values separated by commas.
(z-5)x^2-zx+5=0
Again....if this only has one real root......the discriminant = 0
z^2 - 4(z - 5)(5) = 0
z^2 - 20(z - 5) = 0
z^2 - 20z + 100 = 0
(z - 10) (z -10) = 0
(z - 10)^2 = 0
z - 10 = 0
z = 10
I got this problem wrong on the homework.
+23 
