+0  
 
0
570
1
avatar
how do you solve 3x^2+7x+2=0 by factorisation

and


6x^2+4x-5=0 by completing the square?


thanks
 Jul 21, 2013
 #1
avatar+259 
0
3x^2 + 7x + 2 = 0, factorisation would look as 3(x + 1\3)(x + 2)

6x^ 2+ 4x - 5=0 => 6(x^2 + 4x/6 - 5/6) => 6(x^2 + 2* 4x/6 * 1/2 - 5/6) => 6(x^2 + 2 * x *1/3 + (1/3)^2 - (1/3)^2 - 5/6) =>

=> 6(x^2 + 2 * x *1/3 + (1/3)^2 - 1/9 - 5/6) => 6(x^2 + 2 * x *1/3 + (1/3)^2 - 17/18) => 6(x^2 + 1/3)^2 - 17/3
 Jul 31, 2013

6 Online Users

avatar
avatar