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If the roots of the quadratic equation 1/2*x^2 + 99x + c are x  = -99 - sqrt(7801) and -99 + sqrt(7801), then what is the value of c?

Apr 5, 2021

#1
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$$-99 - \sqrt{7801}= {-b - \sqrt{b^2-4ac} \over 2a}$$

$$-99 - \sqrt{7801}= {-99 - \sqrt{99^2-4(\frac{1}{2})c} \over 2 \cdot \frac{1}{2}}$$

$$\sqrt{7801}= \sqrt{99^2-4(\frac{1}{2})c}$$

$$7801 = 9801 - 2c$$

$$2c = 2000$$

$$c = 1000$$

hope this helps :)

Apr 6, 2021