In an equation of the form with k = ax^2 + bx + c, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x - 12)(x - 8) , what is the least possible value for k?
+36916 (6x-12)(x-8) =
6x^2 -60x+96 bowl shaped parabola least possible value occurs at x = - b/2a = 60/12 = 5
sub in x = 5 to find minumum value of k
k = 6 (5^2) - 60 (5) + 96 = -54
