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In an equation of the form with k = ax^2 + bx + c, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x - 12)(x - 8) , what is the least possible value for k?

 Apr 11, 2021
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(6x-12)(x-8) =

6x^2 -60x+96         bowl shaped parabola    least possible value occurs at x = - b/2a =  60/12 = 5

                                

sub in x = 5   to find minumum value of k

 

k = 6 (5^2) - 60 (5) + 96 = -54

 Apr 11, 2021

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