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What is the minimum value of the expression x^2 + y^2 - 6x + 4y + 18  for real  x and y ?

 Aug 29, 2021
 #1
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Taking the derivative with respect to x and y, we get that the minimum value occurs at x = 6 and y = -4.  This gives us a minimum value of 6^2 + (-4)^2 - 6*6 + 4*(-4) + 18.

 Aug 29, 2021
 #2
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x=3, y=-2

 Aug 29, 2021

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