Let \(3x^2 + 4x + c = 0.\) What value of c will give us exactly one solution for x?
We will have exactly real one solution whenever the discriminant = 0
We have the form ax^2 + bx + c = 0
So....the discriminant is
b^2 - 4ac
4^2 - 4 (3)(c) = 0
16 - 12c = 0
16 =12c
16/12 = c
4/3 = c
Thank you CPhill!
+1306 
