+0  
 
+1
3
1
avatar+73 

Find the sum of the squares of the solutions of \(x^2-13x+4=0\)

 Jun 18, 2024

Best Answer 

 #1
avatar+73 
+1

Let a and b] be the roots of this polynomial. Therefore, a+b=13 and ab=4. Notice that a^2+ab+b^2. This means that the sum of the squares of the roots can be obtained by subtracting the term containing the product of a and b, so a^2+b^2=169-2(4)=161.

 Jun 18, 2024
 #1
avatar+73 
+1
Best Answer

Let a and b] be the roots of this polynomial. Therefore, a+b=13 and ab=4. Notice that a^2+ab+b^2. This means that the sum of the squares of the roots can be obtained by subtracting the term containing the product of a and b, so a^2+b^2=169-2(4)=161.

PurpleWasp Jun 18, 2024

1 Online Users

avatar