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The above figure is quadrilateral \(ABCD\). Given that \(\angle BAD + \angle ACD=145^\circ\), find the measure of \(\angle BAC\) in degrees.

 Jan 30, 2021

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∠BAC = 15º        ∠CAD = ∠ACD = 65º

 

15 + 2 * 65 = 145

 Jan 31, 2021
 #1
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Best Answer

∠BAC = 15º        ∠CAD = ∠ACD = 65º

 

15 + 2 * 65 = 145

Guest Jan 31, 2021

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