In quadrilateral PQRS, PQ = QR = RS = SP, PR = 14, and QS = 48. Find the perimeter of PQRS.
+23246 Given a rhombus with diagonals 14 and 48 -- what is the perimeter?
Since the diagonals of a rhombus are perpendicular to each other, four congruent right triangles are formed.
Each of these triangles have bases of 7 and 24 so we can use the Pythagorean Theorem to find the side
of the rhombus.
c2 = 72 + 242 ---> c2 = 49 + 576 ---> c2 = 625 ---> c = 25.
The perimeter will be 4 x 25 = 100
