1. Find the three other angles of parallelogram ABCD if ∠ A is equal to:
a. 75 degrees b. 62 degrees c. 95 degrees d. 82 1/2 degrees
2. In parallelogram ABCD, if ∠B = (x-5)°, and ∠A=(2x+20)°, find ∠C and ∠D
3. If in parallelogram ABCD, ∠A:∠B = 17:19, find all angles of ABCD.
4.If in parallelogram ABCD, ∠A =(3x+3)° and ∠C=(4x-17)°, find the angles of ABCD.
5. In parallelogram ABCD, if ∠CAB = 35° and ∠BCA=65°, find the angles of ABCD.
6. In parallelogram ABCD, AC meets DB at O
a. If DO=3x-1 and OB=2x+1 , find the length of DB.
b. If AO=3x+1 and OC= 5x-3, find AC
7. In parallelogram ABCD, if ∠BAC= 42° and ∠BCA= 58°, find each angle of ABCD.
8. In parallelogram ABCD, if BC=3x+1 and AD=4x-2, find the lengths of BC and AD.
9. If AB=2x+1, DC=x+5 and BC=2x-1, find all the sides of parallelogram ABCD. Find its perimeter.
If you can provide a figure, please do. I really need this for my report, but I just don't get it.
1. Find the three other angles of parallelogram ABCD if ∠ A is equal to:
a. 75 degrees b. 62 degrees c. 95 degrees d. 82 1/2 degrees
4.If in parallelogram ABCD, ∠A =(3x+3)° and ∠C=(4x-17)°, find the angles of ABCD.
5. In parallelogram ABCD, if ∠CAB = 35° and ∠BCA=65°, find the angles of ABCD.
6. In parallelogram ABCD, AC meets DB at O
a. If DO=3x-1 and OB=2x+1 , find the length of DB.
b. If AO=3x+1 and OC= 5x-3, find AC
7. In parallelogram ABCD, if ∠BAC= 42° and ∠BCA= 58°, find each angle of ABCD.
8. In parallelogram ABCD, if BC=3x+1 and AD=4x-2, find the lengths of BC and AD.
Since parallel sides are equal we have that BC = AD....so...
3x + 1 = 4x - 2 add 2 to both sides.......subtract 3x from both sides
3 = x
So......BC = 3(3) + 1 = 10 = AD
9. If AB=2x+1, DC=x+5 and BC=2x-1, find all the sides of parallelogram ABCD. Find its perimeter.
AB = CD ...so
2x + 1 = x + 5 subtract x, 1 from both sides
x = 4
And AD will = BC.......so the perimeter =
AB + BC + CD + DA =
[2x + 1] + [2x - 1] + [ x + 5] + [ 2x -1] =
[ 2(4) + 1 ] + [ 2(4) - 1] + [ 4 + 5] + [ 2(4) - 1] =
9 + 7 + 9 + 7 = 32