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Rhombus ABCD has perimeter 148, and one of its diagonals has length 28. what is the area of ABCD?

 Apr 2, 2021
 #1
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P = 148          Short diagonal = 28

 

Long diagonal = 2[sqrt(148/4)2 - (28/2)2] = √1173

 

[ABCD] = (28/2) * [(√1173) / 2]

 Apr 2, 2021
 #2
avatar+1203 
+3

correction...

 

[ABCD] = 2 * { (28/2) * [(√1173) / 2]} 

civonamzuk  Apr 2, 2021
edited by civonamzuk  Apr 2, 2021

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