Rhombus ABCD has perimeter 148, and one of its diagonals has length 28. what is the area of ABCD?
P = 148 Short diagonal = 28
Long diagonal = 2[sqrt(148/4)2 - (28/2)2] = √1173
[ABCD] = (28/2) * [(√1173) / 2]
correction...
[ABCD] = 2 * { (28/2) * [(√1173) / 2]}
+1694 
