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Find the perimeter of the parallelogram with these vertices(1,4), (-6,4), (5,-5),(-2,-5)
Give an exact answer (not a decimal approximation).
Simplify your answer as much as possible.

 Mar 23, 2021

Best Answer 

 #1
avatar+9278 
+1

 

perimeter  =  twice the distance between (1, 4) and (-6, 4)   +   twice the distance between (1, 4) and (5, -5)

 

perimeter  =  \(2\cdot\sqrt{(4-4)^2+(-6-1)^2}\ +\ 2\cdot\sqrt{(-5-4)^2+(5-1)^2}\)

 

perimeter  =  \(2\cdot\sqrt{49}\ +\ 2\cdot\sqrt{97}\)

 

perimeter  =  \(2\cdot7\ +\ 2\cdot\sqrt{97}\)

 

perimeter  =  \(14\ +\ 2\sqrt{97}\)

 Mar 23, 2021
 #1
avatar+9278 
+1
Best Answer

 

perimeter  =  twice the distance between (1, 4) and (-6, 4)   +   twice the distance between (1, 4) and (5, -5)

 

perimeter  =  \(2\cdot\sqrt{(4-4)^2+(-6-1)^2}\ +\ 2\cdot\sqrt{(-5-4)^2+(5-1)^2}\)

 

perimeter  =  \(2\cdot\sqrt{49}\ +\ 2\cdot\sqrt{97}\)

 

perimeter  =  \(2\cdot7\ +\ 2\cdot\sqrt{97}\)

 

perimeter  =  \(14\ +\ 2\sqrt{97}\)

hectictar Mar 23, 2021

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