+0  
 
+1
64
1
avatar+621 

The quadratic \(-6x^2+36x+216\) can be written in the form \(a(x+b)^2+c\), where a, b, and c are constants. What is a+b+c?

mathtoo  Aug 27, 2018
 #1
avatar
+1

First factor out a -6 to get \(-6(x^2-6x-36)\)

Then complete the square to get \(-6(x^2-6x+9)+270 ​​\) because 216+54=270

This simplifies to \(-6(x-3)^2+270\)

So \(a=-6\)\(b=-3\), and \(c=270\)  and \(a+b+c=-6+(-3)+270=261\)

Guest Aug 27, 2018

34 Online Users

avatar
avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.