The quadratic \(-6x^2+36x+216\) can be written in the form \(a(x+b)^2+c\), where a, b, and c are constants. What is a+b+c?
First factor out a -6 to get \(-6(x^2-6x-36)\)
Then complete the square to get \(-6(x^2-6x+9)+270 \) because 216+54=270
This simplifies to \(-6(x-3)^2+270\)
So \(a=-6\), \(b=-3\), and \(c=270\) and \(a+b+c=-6+(-3)+270=261\)
+816 
