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# Question 14

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I’ve tried so hard on this, can anyone do it?

The points A (6,1) and B(-2,5) are on the line with equation y=-1/2x+4

M is the midpoint of AB

Find an equation of the line through M that is perpendicular to y=-1/2x+4

Guest Mar 18, 2018
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The points A (6,1) and B(-2,5) are on the line with equation y=-1/2x+4

M is the midpoint of AB

Find an equation of the line through M that is perpendicular to y=-1/2x+4

the gradient of the line   y=-1/2x+4   is    $$-\frac{1}{2}$$

The gradient of the line that is perpendicular is the negative reciprocal which is    $$+\frac{2}{1}=2$$

So 2 will be the gradient of the new line.

The midpoint of AB is simply  the average of the xes and the average of the ys

$$midpoint=(\frac{6+-2}{2},\frac{1+5}{2})\\ midpoint=(\frac{4}{2},\frac{6}{2})\\ midpoint=(2,3)\\$$

So you want the equation of the line through (2,3) with a gradient of 2

there are lots of methods to do this.

Here is one, my start is a bit different from normal, I think it makes it easier because it is the same for many different questions. You just need 2 different ways to express the gradient to make it work.

\begin{align} gradient &=gradient\\ m&=\frac{y-y_1}{x-x_1}\\ 2&=\frac{y-3}{x-2}\\ 2(x-2)&=y-3\\ 2x-4&=y-3\\ 2x-1&=y\\ y&=2x-1 \end{align}

I hope all that helps :)

Melody  Mar 18, 2018