(x+6)+ (x-4 ) + x + (x * 3) = 40
I assume you want to know how to solve this equation. First of all, get rid of all the parentheses because you do not need them and change x*3 to 3x. The equation now looks like x+6+x-4+x+3x=40. Next, combine like terms. There are 6 x's, a 6 and a -4. Combine the 6 x's to get 6x and add the 6 and -4 together to get 2. Now the equation looks like 6x+2=40. Next subtract 2 from each side and the equation now looks like 6x=38. Divide 6 to each side and you get x=6 1/3 or 19/3. To see if the answer is correct, in the original equation, substitute x for 6 1/3 or 19/3; I will be using 19/3. The equation will look like (19/3+6)+(19/3-4)+19/3+(19/3*3)=40. Add 19/3 and 6 together and the equation now looks like 37/3+(19/3-4)+19/3+(19/3*3)=40. Now subtract 4 from 19/3 and the equation now looks like 37/3+7/3+19/3+(19/3*3)=40. Now multiply 19/3 and 3 to get the equation looking like 37/3+7/3+19/3+57/3=40. Now add 37/3 and 7/3 together and the equation looks like 44/3+19/3+57/3=40. Now add 44/3 and 19/3 together to make the equation look like 63/3+57/3=40. Now add 63/3 and 57/3 together to get the equation to look like 120/3=40. Next divide 3 from 120 and get 40=40. This proves that x does equal 19/3. Hope this helps.
