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What is the area of the circle defined by x^2 + 8x + y^2 - 14y + 61 = 0 that lies beneath the line y=7 ?

 Dec 17, 2020
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Complete the square on x , y

 

x^2 +8x + 16   + y^2 - 14y + 49   =   16  + 49

 

( x + 4)^2  +  ( y - 7)^2  =   65

 

The center is  ( - 4, 7)

 

The line y = 7   will create two half- circles

 

So  (1/2)  of the area of the circle will lie below y =7

 

 

 

cool cool cool 

 Dec 17, 2020

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