A stack contains 7 green marbles and 3 red marbles. 2 marbles are taken from the sack w/out replacement. What is the probability of taking one green marble and one red marble (in any order)?
A stack contains 7 green marbles and 3 red marbles. 2 marbles are taken from the sack w/out replacement. What is the probability of taking one green marble and one red marble (in any order)?
P(Green followed by Red) = \(\frac{7}{10}*\frac{3}{9}=\frac{21}{90}\)
Now do something very similar to get the prob of a red followed by a green.
Then add the answers together and simplify.