Determine the value of x to the nearest tenth of a centimetre.
Angle B in the smaller( isosceles) triangle = (180 -70) / 2 = 55°
So we can find the base of the larger triangle as
base /sin70 = 27/sin55
base = 27*sin 70 / sin 55 ≈ 31
So
x = 31/sin27 ≈ 68.3°
