n[A ∪ (B ∩ C)]
I assume the 'n' means 'not'
find A color it in find the intersection of B and C (B ∩ C) color it in
everything not colored is the n[A ∪ (B ∩ C)]
not[A ∪ (B ∩ C)] = ( not A ∩ not B ) ∪ ( not A ∩ not C )
+36916 
