\(\text{A parabola with equation $y=ax^2+bx+c$ contains the points $(-3,3)$, $(1,3)$, and $(0,0)$. Find the value $100a+10b+c$. }\)
Thanks! 
+128400 If (0,0) is on the graph, then c = 0
So.....we have these two equations
a(-3)^2 + b(-3) = 3 ⇒ 9a - 3b = 3 (1)
a(1)^2 + b(1) = 3 ⇒ a + b = 3 ⇒ 3a + 3b = 9 (2)
Add (1) and (2) and we have that
12a = 12
a = 1
And using (1)
9)1) - 3(b) = 3
9 - 3b = 3
-3b = -6
b = 2
So 100a + 10b + c = 100(1) + 10(2) + 0 = 100 + 20 = 120
