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Solve   \(\frac{3x^2+2x+1}{x-1}=3x+1\) for x.

tertre  Mar 12, 2017
 #1
avatar+7153 
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\(\frac{3x^2+2x+1}{x-1}=3x+1\)

 

Multiply both sides by (x - 1).

3x2 + 2x + 1 = (3x + 1)(x - 1)

 

Multiply out the left side.

3x2 + 2x + 1 = 3x2 - 3x + x - 1

 

Combine like terms.

3x2 + 2x + 1 = 3x2 - 2x - 1

 

Subtract 3x2 from both sides.

2x + 1 = -2x - 1

 

Add 2x to both sides.

4x + 1 = -1

 

Subtract 1 from both sides.

4x = -2

 

Divide both sides by 4.

x = -2/4

x = -1/2

hectictar  Mar 12, 2017

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