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One month Milan rented 2 movies and 6 video games for a total of $38 . The next month he rented 5 movies and 3 video games for a total of $32 . Find the rental cost for each movie and each video game.

 Nov 24, 2015
 #1
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One month Milan rented 2 movies and 6 video games for a total of $38 . The next month he rented 5 movies and 3 video games for a total of $32 . Find the rental cost for each movie and each video game

 

Let m=price per movie

Let v=price per video

 

2m + 6v=38, and

5m + 3v=32

 

Solve the following system:
{2 m+6 v = 38 |     (equation 1)
5 m+3 v = 32 |     (equation 2)
Swap equation 1 with equation 2:
{5 m+3 v = 32 |     (equation 1)
2 m+6 v = 38 |     (equation 2)
Subtract 2/5 × (equation 1) from equation 2:
{5 m+3 v = 32 |     (equation 1)
0 m+(24 v)/5 = 126/5 |     (equation 2)
Multiply equation 2 by 5/6:
{5 m+3 v = 32 |     (equation 1)
0 m+4 v = 21 |     (equation 2)
Divide equation 2 by 4:
{5 m+3 v = 32 |     (equation 1)
0 m+v = 21/4 |     (equation 2)
Subtract 3 × (equation 2) from equation 1:
{5 m+0 v = 65/4 |     (equation 1)
0 m+v = 21/4 |     (equation 2)
Divide equation 1 by 5:
{m+0 v = 13/4 |     (equation 1)
0 m+v = 21/4 |     (equation 2)
Collect results:
Answer: | m=13/4=$3.25  and  v=21/4=$5.25
 

 Nov 24, 2015
 #2
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m=movie v=video

Then 2m + 6v = 38     and   5m + 3v = 32

Solve FIRST equation for v  

6v=(38-2m)

v= (38-2m)/6     Substitue this into the SECOND equation and solve for 'm'

5m + 3 (38-2m)/6 =32

10m + 38 -2m = 64

8m= 26    or m= $ 3.25

Now sub into one of the two equations to find v

2(3.25) + 6v = 38

6v=31.5  or v = $ 5.25

 Nov 24, 2015

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