question

Samah:

Calculate g'(x),where g(x) is the inverse of f(x).
f(x)=x^-3

f(x)=x^-3=1/(x^3)

2 => 1/8
3 => 1/27

g'(x)=sqrt3( 1/x )

simplified test:
g'( f(x) ) = sqrt3( 1/( 1/(x^3) ) ) = sqrt3( x^3 ) = x