question x = ?
sinx +cosx = √6/2
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sinx+cosx=12√2sinx+√1−sin2x=12√2sinx=uu+√1−u2=12√2√1−u2=12√2−u sinx−√1−sin2x=12√2 (also pursue!)
1−u2=12−√2⋅u+u22u2−√2⋅u−12=0u2−12√2⋅u−14=0
u=14√2±√18+14u=14√2±√38
u1=sinx1=0.96592u2=sinx2=−0.25882
x1=105°x2=−15°
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